{"id":768,"date":"2025-01-12T11:58:00","date_gmt":"2025-01-12T06:28:00","guid":{"rendered":"https:\/\/jollymaths.com\/blog\/?p=768"},"modified":"2025-10-22T12:24:29","modified_gmt":"2025-10-22T06:54:29","slug":"how-to-make-date-of-birth-magic-square-swami-vivekananda-birth-anniversary-12-1-2025","status":"publish","type":"post","link":"https:\/\/jollymaths.com\/blog\/how-to-make-date-of-birth-magic-square-swami-vivekananda-birth-anniversary-12-1-2025\/","title":{"rendered":"How to make Date of Birth Magic Square ( Swami Vivekananda birth Anniversary 12-1-2025)"},"content":{"rendered":"\n
\"\"<\/figure>\n\n\n\n
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  1. Swami Vivekananda Birth Anniversary is 12-1-2025. <\/li>\n\n\n\n
  2. \u00a0Let us see how to make a magic square for 12-1-2025.<\/li>\n\n\n\n
  3. Draw 4 x 4 empty magic squares and fill 12 (Day), 1 (Month),\u00a0\u00a0\u00a0 20 (Century) and 25 (Current year) separately.<\/li>\n<\/ol>\n\n\n\n

    4) Count all numbers 12 + 1 + 12 + 25 = 58<\/p>\n\n\n\n

    5) In a separate 4 x 4 square replace all numbers as A, B, C, D etc as shown in the right side square\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Now A = 12, B = 1, C = 20 and D =25. Rest all value we have to find out.<\/strong><\/p>\n\n\n\n

    \u00a0\u00a0\u00a0\u00a0 6)\u00a0 Now count all the numbers of 58 in the top and make it a single digit. \u00a0 \u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0i.e. 5 + 8 = 13, once again 1 + 3 = 4 and place it the H square. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 ( H value is 4.)<\/strong><\/p>\n\n\n\n

    7) Now add B + C i.e. (1 + 20 ) = 21 and split \u00a0it into two parts. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Let it be 11 and 10. Now Place them in W and Z i.e.\u00a0 W=11 and Z=10.<\/strong><\/p>\n\n\n\n

    8) Now remember, in a magic square all the vertical, Horizontal and both Diagonal totals are equal and for this square it will be 58.<\/strong><\/p>\n\n\n\n

    \u00a0\u00a0\u00a0\u00a0 9) To find S, add D + H + Z and subtract it from 58.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 i.e.58 – (25 + 4 + 10)\u00a0 = 58 \u2013 39 = 19.\u00a0\u00a0 Hence S = 19<\/strong><\/p>\n\n\n\n

    10) Now to find the value of Q and G, add ( D + W ) and deduct it from 58.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0ie. 58 \u2013 (11 + 25 ) = \u00a058 \u2013 36 = 22 . \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0Make it two parts. Let it be 13 and 9.\u00a0 Hence place Q = 13 and G =9<\/strong>.<\/p>\n\n\n\n

    \u00a0\u00a0\u00a0\u00a0 11)\u00a0 Now to find F and R, add A and Z and deduct it from 58. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 i.e.58 – (12 + 10) = 58 \u2013 22 = 36 . \u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Spilt it into two parts.\u00a0 Let it be 15 \u00a0and 21.\u00a0\u00a0 Place F =15 and R= 21<\/strong><\/p>\n\n\n\n

    \u00a0\u00a0\u00a0 12) Now to find E, add ( F + G + H ) and deduct it from 58. \u00a0 \u00a0 \u00a0i.e. 58 \u2013 ( 15 +\u00a0 9 + 4 ) = 58 \u2013 28 = 30.\u00a0 Hence E = 30.<\/strong><\/p>\n\n\n\n

    \u00a0\u00a0 13) Now to find P, Add ( Q + R +\u00a0 S ) and<\/strong> deduct it from 58. \u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0i.e. 58 – (13 + 21 + 19) = 58 \u2013 53 = 5 . \u00a0Hence P = 5.<\/strong><\/p>\n\n\n\n

    14)\u00a0 Now we found the values of A, E, P, W.\u00a0 Let us check whether \u00a0<\/strong> \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 A + E + P + W = 58.\u00a0 12 + 30 + 5 + 11 = 58.\u00a0 OK.<\/strong><\/p>\n\n\n\n

    \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 We can proceed further.<\/strong><\/p>\n\n\n\n

    \u00a015) To find X, add B + F + Q <\/strong>and deduct from 58.\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 I.e. 58 \u2013 ( 1 + 15 + 13 ) = 58 \u2013 29 = 29.\u00a0 Hence X = 29.<\/strong><\/p>\n\n\n\n

    16) \u00a0And finally to find Y, add C + G + R<\/strong> and deduct it from 58.\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0i.e. 58 – ( 20 + 9 + 21 ) = 58 \u2013 50 = 8. \u00a0\u00a0\u00a0Hence Y= 8.<\/strong><\/p>\n\n\n\n

    17) \u00a0\u00a0Now Finally add W + X + Y + Z =\u00a0 11 + 29 + 8 + 10 = 58.<\/strong><\/p>\n\n\n\n

      Waaaaw!!!  You have got the magic square for 12 \u2013 1 -2025, with all vertical, Horizontal and Both diagonal totals are 58.<\/strong><\/p>\n\n\n\n

    Remember.. You can make millions of magic squares for this date with the same total 58<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"

    4) Count all numbers 12 + 1 + 12 + 25 = 58 5) In a separate 4 x 4 square replace all numbers as A, B, C, D etc as shown in the right side square\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Now A = 12, B = 1, C = 20 and D =25. Rest all value we have … Continue reading How to make Date of Birth Magic Square ( Swami Vivekananda birth Anniversary 12-1-2025)<\/span> →<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-768","post","type-post","status-publish","format-standard","hentry","category-uncategorized"],"_links":{"self":[{"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/posts\/768","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/comments?post=768"}],"version-history":[{"count":1,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/posts\/768\/revisions"}],"predecessor-version":[{"id":770,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/posts\/768\/revisions\/770"}],"wp:attachment":[{"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/media?parent=768"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/categories?post=768"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/tags?post=768"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}