{"id":41,"date":"2013-11-02T19:36:04","date_gmt":"2013-11-02T14:06:04","guid":{"rendered":"http:\/\/jollymaths.com\/blog\/?p=41"},"modified":"2021-01-24T11:34:40","modified_gmt":"2021-01-24T06:04:40","slug":"how-to-construct-a-magic-square-for-a-given-date","status":"publish","type":"post","link":"https:\/\/jollymaths.com\/blog\/how-to-construct-a-magic-square-for-a-given-date\/","title":{"rendered":"How to construct a Magic Square for a Given Date"},"content":{"rendered":"\n<p><\/p>\n\n\n<p>Let us do magic square to the date of Birth of our Greatest\u00a0 Indian Mathematician Sri Srinivasa Ramanujan.<\/p>\n<p>His date of Birth is 22nd Dec 1887. The following is a Date-Of-Birth Magic Square with a Magic Total 139.<\/p>\n<p><strong>By following the given method we can do hundreds of, thousands of, millions of Date of Birth Magic Squares for any given date.<\/strong><\/p>\n<p>The following is a table with variables, which we will use in the explanation<\/p>\n<h5><a href=\"http:\/\/jollymaths.com\/blog\/wp-content\/uploads\/2013\/11\/All-Power-points.jpg\" class=\"gallery_colorbox\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-330\" src=\"http:\/\/jollymaths.com\/blog\/wp-content\/uploads\/2013\/11\/All-Power-points.jpg\"  alt=\"Date of Birth Magic Square - Srinivasa Ramanujan\" width=\"960\" height=\"720\" srcset=\"https:\/\/jollymaths.com\/blog\/wp-content\/uploads\/2013\/11\/All-Power-points.jpg 960w, https:\/\/jollymaths.com\/blog\/wp-content\/uploads\/2013\/11\/All-Power-points-300x225.jpg 300w, https:\/\/jollymaths.com\/blog\/wp-content\/uploads\/2013\/11\/All-Power-points-768x576.jpg 768w\" sizes=\"auto, (max-width: 960px) 100vw, 960px\" \/><\/a><\/h5>\n<ol>\n<li>Write the date in the top row first square, month in the second square and year in two parts in the third and fourth square.<\/li>\n<li>Add all the four numbers and write on the top of the square (139).<\/li>\n<li>Now we have to make a 4 x 4 magic square.<\/li>\n<li>Draw a empty 4 x 4 square and replace <strong>22 by A,\u00a0 \u00a012 by B,\u00a0 \u00a018 by C and 87 by D.<\/strong><\/li>\n<li>Now we know\u00a0 <strong>A,B,C and D<\/strong>.\u00a0 \u00a0Rest of the values we have to find out.<\/li>\n<li>Count all numbers in the total <strong>1+3+9=13.<\/strong> Once again count\u00a0 <strong>1+3=4.<\/strong> (add all numbers and make it a single digit. <strong>Write this in the H square<\/strong><\/li>\n<li>Now add <strong>B+C ( 12 + 18 =30)<\/strong>. Divide <strong>30 into two parts. i.e 14 and 16.<\/strong> Write <strong>14 in W<\/strong> square and <strong>16 in the Z square<\/strong><\/li>\n<li>By using the properties of Magic square, i.e all vertical, Horizontal and both Diagonal totals are equal, we are going to solve this Magic Square.<\/li>\n<li>In the Fourth vertical column, we know the values of <strong>D,H,Z.<\/strong> we have to find Out the value of S. Hence <strong>S = 139 \u2013 (D+H+Z) = 139 &#8212; ( 87+4+16) = 139 \u2013 107 = 32.<\/strong> <strong>This is the value of S. Write 32 in the S square<\/strong><\/li>\n<li>Now in Diagonals, we know the value of <strong>A and Z .<\/strong> Hence the value of<strong> F + R\u00a0= 139 \u2013 (22 + 16) = 139-38= 101. Divide it into two parts 50 and 51 <\/strong>and write it in the F and R squares. <strong>F = 50 and R = 51.<\/strong><\/li>\n<li>In another diagonal, we know the value of D and W . Hence the value of\u00a0 <strong>G+Q = 139 \u2013 (87 + 14) = 139-101= 38.<\/strong> Divide it into two parts 17 and 21 and write it in the F and R squares. <strong>G = 17 and Q = 21.<\/strong><\/li>\n<li>In the second row, we know the value of <strong>E,G,H. H<\/strong>ence value of<strong> E=139-(E+G+H)= 139 \u2013( 50+17+4)= 139 \u2013 71 = 68. Write 68 in E.<\/strong><\/li>\n<li>In the third row, we know the value of <strong>Q,R,S.<\/strong> Hence value of <strong>P=139-(Q+R+S)= 139 \u2013(21+51+32)= 139 \u2013 104 = 35. Write 35 in P.<\/strong><\/li>\n<li>Now in the second vertical column, we know the values of <strong>B,F,Q.<\/strong> Hence value of <strong>X = 139 \u2013 (12+50+21) = 139- 83 = 56. Write 56 in X<\/strong><\/li>\n<li>Now in the third vertical column, we know the values of <strong>C,G,R.<\/strong> Hence value of <strong>X = 139 \u2013 (18+17+51) = 139- 86 = 53. Write 53 in Y<\/strong><\/li>\n<li>Now add the values of W,X,Y and Z. You will\u00a0 get 139 is the total.<\/li>\n<\/ol>\n<p>Hurray!!! <strong>MAGIC SQUARE FOR 22-12-1887 IS READY<\/strong><\/p>\n<p><strong>In step number 10, we have divided 101 into 50 and 51.\u00a0 Instead it can be divided into q and 101 or 1 and 100 or 2 and 99 etc. etc&#8230; Interestingly we can divide it as -1 and 102 or -2 and 103 or -3 ans 104 etc.\u00a0 While dividing each number, if the numbers are slightly changed, we can get a new Magic square.\u00a0\u00a0<\/strong><\/p>\n<p><strong>Hence we can make hundreds of, thousands of, millions of date of birth magic squares for any given date<\/strong><\/p>\n<p><strong>Enjoy Magic square for your date of Birth!!!\u00a0 \u00a0 In various methods&#8230;.<\/strong><\/p>","protected":false},"excerpt":{"rendered":"<p>Let us do magic square to the date of Birth of our Greatest\u00a0 Indian Mathematician Sri Srinivasa Ramanujan. His date of Birth is 22nd Dec 1887. The following is a Date-Of-Birth Magic Square with a Magic Total 139. By following the given method we can do hundreds of, thousands of, millions of Date of Birth &hellip; <a href=\"https:\/\/jollymaths.com\/blog\/how-to-construct-a-magic-square-for-a-given-date\/\" class=\"more-link\">Continue reading <span class=\"screen-reader-text\">How to construct a Magic Square for a Given Date<\/span> <span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2,8,9],"tags":[19],"class_list":["post-41","post","type-post","status-publish","format-standard","hentry","category-magic-square","category-recreational-math","category-recreational-mathematics","tag-tutorial-2"],"_links":{"self":[{"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/posts\/41","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/comments?post=41"}],"version-history":[{"count":10,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/posts\/41\/revisions"}],"predecessor-version":[{"id":648,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/posts\/41\/revisions\/648"}],"wp:attachment":[{"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/media?parent=41"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/categories?post=41"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/jollymaths.com\/blog\/wp-json\/wp\/v2\/tags?post=41"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}